DeAndre Hopkins Incredible Season Lands Him on the NFL All-Pro First Team

In the six games that Deshaun Watson started, DeAndre Hopkins caught 96 passes for 1,378 yards and scored 13 touchdowns. This incredible feat is why Hopkins has found himself named to the NFL All-Pro First Team. What makes this even more astonishing is the fact that for the games in which Watson did not start, nine to be exact, Hopkins made the most out of what was available to him, which wasn’t much. It only took him six games to show that he remains one of the best wide receivers in the NFL.

While Hopkins is the only Texan to make an All-Pro team this year, he is in good company as a Texan seeing that the last wide receiver to make this special squad was Andre Johnson.

Hopkins said of this achievement, “This is a personal goal I’ve had since I’ve been in the NFL. It’s an accomplishment I’ve been striving for…It’s great to be in the Pro Bowl, but once you’re considered first-team All-Pro, it goes a long way.”

The votes were cast by a panel of 50 people that included former players, NFL media members and personnel executives.

Hopkins went on to say, “This is motivation for me to stay at the top of my game. This is motivation to keep working harder and not just be the No. 1 or No. 2 receiver for one year of my career.”

Hopkins led the league in touchdown catches, is first in catches of at least 25 yards, fourth in yardage, fourth in first-down catches, third in 100-yard games, and finished sixth in receptions.

“I’m very thankful,” Hopkins said. “I want to thank my quarterbacks for trusting in me and helping me get that accomplishment…I want more. That’s the way I play this game. When your teammates see you want more, they want more. They strive to become better, too, and expect more from themselves. If I hold myself to a higher caliber and not be satisfied with my accomplishments, I feel like my teammates will, too.”

Congratulations to DeAndre Hopkins on yet another incredible season.